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Apr 22, 2010 at 16:40 comment added George McNinch @Pete: yes, that is correct.
Feb 25, 2010 at 16:25 answer added Guntram timeline score: 3
Feb 16, 2010 at 7:27 comment added Pete L. Clark If I am underanding things correctly now, the orthogonal group of a quadratic form will be split iff the quadratic form has maximal Witt index $\lfloor \operatorname{dim}(q)/2 \rfloor$?
Feb 15, 2010 at 23:33 comment added Pete L. Clark @Kevin: Yes, I see it now. I was thinking of the three-dimensional case for part of my argument and of the > three-dimensional case for another part.
Feb 15, 2010 at 23:16 comment added Kevin Buzzard Pete: I think these groups aren't going to be split in general.
Feb 15, 2010 at 22:40 vote accept blt
Feb 15, 2010 at 22:34 answer added BCnrd timeline score: 8
Feb 15, 2010 at 22:07 comment added Pete L. Clark Does the existence of isotropic quadratic forms over Q which are not similar give a counterexample (via the orthogonal groups)?
Feb 15, 2010 at 21:58 history asked blt CC BY-SA 2.5