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Jan 4, 2014 at 10:59 comment added Campello Oh. This is exactly what Brendan commented above. Sorry dude.
Jan 4, 2014 at 10:57 comment added Campello You may want to try the same ideias to obtain a Taylor Series approximation around any point $p$. And you may also calculate the sum in $n$ (geometric progression) and then do Taylor Approximation... some of these thechniques may suffice...
Jan 4, 2014 at 10:26 comment added Brendan McKay Of course. As $p$ approaches 0, the sum approaches $n$ but this approximation doesn't.
Jan 4, 2014 at 5:40 comment added Kelvin Lee I assumed $p$ was very small and maybe very close to $0$, say 1e-2, 1e-3, or 1e-4, will that complicate the approximation?
Jan 4, 2014 at 1:41 history answered Campello CC BY-SA 3.0