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Apr 6, 2014 at 8:23 vote accept Ali Taghavi
Jan 7, 2014 at 10:42 answer added alvarezpaiva timeline score: 7
Jan 7, 2014 at 10:02 history edited alvarezpaiva CC BY-SA 3.0
Corrected spelling and a little editing
Jan 4, 2014 at 10:13 comment added Ali Taghavi I apologize for several changing the true exponent. it was because of my miss computation. the true exponent is 2n , because the volume of a $\rho$-disk in $\mathbb{R}^{2n}$ is of order $\rho^{2n}$. On the other hand a symplectic embedding preserve the volume
Jan 4, 2014 at 10:04 history edited Ali Taghavi CC BY-SA 3.0
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Jan 4, 2014 at 8:21 comment added Ali Taghavi Thank you for your comment on the "exponent".motivating by $M=S^{1}$,(and $M=\mathbb{T}^{n}$) we observe that the true power must be "2", otherwise the above limit goes to 0 or infinity.
Jan 4, 2014 at 8:14 history edited Ali Taghavi CC BY-SA 3.0
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Jan 4, 2014 at 7:28 comment added Ali Taghavi In the revised version I wrote the definition of symplectic capacity. Moreover the true exponent is not $n$ but is $2n$, the dimension of total space. I edited it know
Jan 4, 2014 at 7:25 history edited Ali Taghavi CC BY-SA 3.0
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Jan 4, 2014 at 0:51 comment added Marco Golla What is the capacity you're referring to? Could you give a reference? Could you also provide some motivation for the question? In particular, why should the exponent be exactly $n$? Finally, have you tried computing any reasonable example (e.g. tori, products...)?
Jan 3, 2014 at 23:25 history edited Ali Taghavi
edited tags
Jan 3, 2014 at 23:10 history asked Ali Taghavi CC BY-SA 3.0