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Apr 22, 2014 at 3:02 answer added Joe Fu timeline score: 3
Mar 23, 2014 at 0:30 answer added Connor Mooney timeline score: 1
Jan 8, 2014 at 10:07 comment added username If you can reduce the problem to the case (by an adequate change of coordinates?) where $f(0)=0$, $f$ is even and there is a sequence $(0,-\epsilon_n)$ with two closest points (therefore strictly below the horizontal axis on the graph), you are done, I think, as for any finite constant, $C$, $f(x)+Cx^2$ would not be convex in zero.
S Jan 7, 2014 at 14:59 history suggested username CC BY-SA 3.0
just to clarify
Jan 7, 2014 at 14:55 review Suggested edits
S Jan 7, 2014 at 14:59
Jan 3, 2014 at 19:15 history edited Ricardo Andrade CC BY-SA 3.0
removed inappropriate tag; added top level tag; added definition to clarify question
Jan 3, 2014 at 17:03 comment added Deane Yang Perhaps you could provide the definition of reach in the question.
Jan 3, 2014 at 15:21 history edited Suvrit CC BY-SA 3.0
improved formatting a bit
Jan 3, 2014 at 14:17 comment added John6 The original Federer's definition: link page 15 (p 432)
Jan 3, 2014 at 13:08 comment added Alex Degtyarev What is the reach of a set?
Jan 3, 2014 at 12:54 review First posts
Jan 3, 2014 at 12:54
Jan 3, 2014 at 12:38 history asked John6 CC BY-SA 3.0