Timeline for Equality of elements in localization via universal property
Current License: CC BY-SA 2.5
4 events
when toggle format | what | by | license | comment | |
---|---|---|---|---|---|
Jun 25, 2013 at 3:02 | review | Late answers | |||
Jun 25, 2013 at 14:05 | |||||
Mar 8, 2010 at 21:11 | comment | added | user3795 | Fair enough. They are in the case where $A$ is a commutative ring with unit and $1\in A$. Should have written those pre-suppositions into my write-up above (which I have improved upon personally but not yet edited). It also is unclear in your original question exactly what isomorphism (or equality) you want to show via the universal property. | |
Mar 8, 2010 at 13:42 | comment | added | Martin Brandenburg | No. $A$ and $S^{-1} A$ are not isomorphic. | |
Feb 15, 2010 at 15:57 | history | answered | user3795 | CC BY-SA 2.5 |