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Feb 12, 2014 at 6:04 comment added Allen Knutson If $G=PGL_n$, then $Gr$ has $n$ components, each of which contains a unique minimal $Gr^\lambda$. The minimal $Gr^\lambda$ in the $k$th component of $Gr$ is the ordinary Grassmannian $Gr(k,n)$.
Dec 30, 2013 at 17:53 comment added Peter Crooks I think the idea is to first realize $Gr_G$ as the affine Grassmannian discussed in Pressley-Segal. (The equivalence of these versions is the subject of mathoverflow.net/questions/150171/…) The Pressley-Segal version of the affine Grassmannian is defined in terms of subspaces of some Hilbert space satisfying some technical analytic conditions.
Dec 30, 2013 at 17:27 comment added Dori Bejleri How does this relate to the usual Grassmannian?
Dec 30, 2013 at 14:29 history edited Peter Crooks CC BY-SA 3.0
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Dec 30, 2013 at 14:09 vote accept Jianrong Li
Dec 30, 2013 at 13:55 history answered Peter Crooks CC BY-SA 3.0