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Dec 27, 2013 at 19:36 vote accept Marc Nieper-Wißkirchen
Dec 27, 2013 at 16:13 comment added Michael Bächtold One might add the (maybe trivial) remark that if $I$ is differentially generated by forms $\omega_1,\ldots,\omega_k$ then it's generated as a $K[x_1,\dots,x_n]$ submodule by $\omega_i,\omega_i\wedge dx^I, d\omega_i,d\omega_i\wedge dx^I$.
Dec 27, 2013 at 14:23 history answered Will Sawin CC BY-SA 3.0