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Dec 26, 2013 at 17:15 vote accept Jonathan Beardsley
Dec 26, 2013 at 9:04 comment added Denis Nardin Oh and just to be precise: I never require $Aut(X)$ or any torsor to be representable, so $Aut(X)$ is a sheaf of groups in our site and a torsor $T$ is a sheaf of sets with an action $T\times Aut(X)\to T$ which is simply transitive (i.e. $T\times Aut(X)\to T\times T$ is an isomorphism). These are the objects classified by the first Cech cohomology group.
Dec 26, 2013 at 8:57 comment added Denis Nardin Well I am imagining $F$ to be a sheaf of groupoids on some site, which could be the fpqc if you want (if you want I can write down the proof, it's actually easier than I remembered at first)
Dec 26, 2013 at 3:56 comment added Jonathan Beardsley And I might add, in case anyone doesn't know, that cohomology group rightfully computes torsors for $Aut(A)$ over $X$, hence Denis only explaining how $B$ gets taken to an $Aut(A)$-torsor.
Dec 26, 2013 at 3:44 comment added Jonathan Beardsley Thanks Denis!! Are you assuming the cover is faithfully flat here? (And Merry Christmas to you too!)
Dec 25, 2013 at 14:48 comment added Denis Nardin During Christmas lunch I realized that the proof I know works for every sheaf of groupoids $F$ (a.k.a. stack) on your site, so if you want you can ignore the description of ''algebraic structures'' (apart from being nice examples of stacks. Oh and merry christmas everyone!
Dec 24, 2013 at 12:35 history edited Denis Nardin CC BY-SA 3.0
corrected formattation mistake
Dec 24, 2013 at 12:29 history answered Denis Nardin CC BY-SA 3.0