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Dec 27, 2013 at 19:36 vote accept Marc Nieper-Wißkirchen
Dec 27, 2013 at 16:16 comment added Michael Bächtold Somewhat related but probably harder: mathoverflow.net/questions/47657
Dec 27, 2013 at 14:23 answer added Will Sawin timeline score: 5
Dec 26, 2013 at 6:48 comment added Marc Nieper-Wißkirchen The ring $\Omega$ is super-commutative; the generators $x_i$ are of degree $0$, the generators $dx_i$ are of degree $1$. There is just one differential operator, the derivative $d$ of degree $1$, which fulfills $d \circ d = 0$, that is $d(dx_i) = 0$.
Dec 25, 2013 at 16:06 comment added Will Sawin What is $D(dx_1)$?
Dec 21, 2013 at 9:43 history asked Marc Nieper-Wißkirchen CC BY-SA 3.0