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Dec 20, 2013 at 7:51 vote accept Ali Taghavi
Dec 19, 2013 at 17:18 history closed Ricardo Andrade
Benoît Kloeckner
Andrey Rekalo
Ryan Budney
Stefan Kohl
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Dec 19, 2013 at 15:31 review Close votes
Dec 19, 2013 at 17:18
Dec 19, 2013 at 15:19 comment added Ricardo Andrade Since $df : TM \to TN$ covers $f$, it induces a map $TM \to f^\ast TN$ over $\mathrm{id}_M$, which I also called $df$ above.
Dec 19, 2013 at 15:15 comment added Ali Taghavi $df$ cover $f$, but an isomorphism of two vector bundles on $M$ must cover $Id_{M}$
Dec 19, 2013 at 15:12 comment added Ricardo Andrade Doesn't every diffeomorphism $f : M \to N$ induce an isomorphism $df : TM \to f^\ast TN$?
Dec 19, 2013 at 15:06 answer added Andreas Blass timeline score: 2
Dec 19, 2013 at 15:01 history asked Ali Taghavi CC BY-SA 3.0