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Dec 19, 2013 at 21:41 comment added Tom LaGatta Thank you, @Peter. I've modified my question to avoid this trivial example.
Dec 19, 2013 at 21:41 history edited Tom LaGatta CC BY-SA 3.0
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Dec 19, 2013 at 2:47 comment added Peter Michor Since $Y= Im(I_Y) = Im(f\circ g)\subseteq Im(f)$, $f$ is surjective, and there are counterexamples, like $f=I_X$.
Dec 18, 2013 at 20:33 review Close votes
Dec 18, 2013 at 22:51
Dec 18, 2013 at 18:56 history asked Tom LaGatta CC BY-SA 3.0