Timeline for Is the tangent bundle of hyperbolic space trivial?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 18, 2013 at 0:15 | comment | added | Igor Belegradek | Reagarding 2, a natural guess is that the isometry group is $\mathrm{Iso}(H)$, which certainly acts isometrically. Fibers are flat. With these two facts in mind, the curvature formulas (see above master thesis) should provide enough information to answer 2. | |
| Dec 18, 2013 at 0:12 | history | edited | Igor Belegradek | CC BY-SA 3.0 |
added 12 characters in body
|
| Dec 18, 2013 at 0:11 | comment | added | Igor Belegradek | Search online for for master thesis "NATURAL METRICS ON TANGENT BUNDLES" by ELIAS KAPPOS. There is stated that if the tangent bundle with Sasaki metric has bounded sectional curvature, then it is flat. This answers 1 because the product of of a hyperbolic and Euclidean space has curvature in $[-1,0]$ but it also has a non-virtually abelian discrete isometry group, i.e. a hyperbolic lattice. | |
| Dec 17, 2013 at 22:10 | review | First posts | |||
| Dec 17, 2013 at 22:12 | |||||
| Dec 17, 2013 at 21:53 | history | asked | Hyperbolic Asker | CC BY-SA 3.0 |