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Dec 16, 2013 at 14:46 comment added Aleksa Ah, I see. I was thinking for situation like you have derived McKay correspondence $F:D^b_G(X\otimes_{\mathbb{R} }\mathbb{C})\rightarrow D^b(Y\otimes_{\mathbb{R}}\mathbb{C})$ and a object $\mathcal{K}$ in $D^b_G(X\otimes_{\mathbb{R} }\mathbb{C})$ that descents to $D^b_G(X)$. I am interessted in $F(\mathcal{K})$ ? I do not see why this should descent...
Dec 16, 2013 at 14:34 history answered Jeremy Rickard CC BY-SA 3.0