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Dec 16, 2013 at 15:37 comment added Jonathan Beardsley The equivalence you write, $\pi^\ast\mathcal{K}\simeq\mathcal{T}$, is this a homotopy equivalence?
Dec 16, 2013 at 14:34 answer added Jeremy Rickard timeline score: 1
Dec 16, 2013 at 13:30 history asked Aleksa CC BY-SA 3.0