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Sep 22, 2016 at 11:59 vote accept Ingo Blechschmidt
Sep 21, 2016 at 23:25 answer added HeinrichD timeline score: 7
Sep 21, 2016 at 18:53 comment added Ingo Blechschmidt @HeinrichD: Thanks! I'd be willing to accept this as an answer. You can show that the decomposition is unique by verifying that irreducible elements are prime; this is possible with Euclid's lemma (which holds in GCD domains and which admits a constructive proof). Furthermore, one can show that a domain is an UFD in their sense if and only if it is a UFD in the sense of my question and associatedness of irreducible elements is decidable.
Sep 16, 2016 at 19:09 comment added HeinrichD It seems that Lombardi and Quitté in their book "Commutative Algebra: Constructive Methods" define UFDs as GCD-domains such that every regular element is a product of irreducibles (does this classically coincide with the usual definition, i.e. is the decomposition unique?).
Dec 15, 2013 at 16:38 history asked Ingo Blechschmidt CC BY-SA 3.0