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Dec 14, 2013 at 19:28 comment added Marc Palm Just to be clear, the spherical part is infinite dimensional because $L^2(\Gamma \backslash G /K)$ is and the one-dimensional only a subspace of the spherical part. We don't know in general if the cuspidal part is infinite-dimensional, but only in the congruence setting (Weyl law).
Dec 14, 2013 at 19:27 history edited Marc Palm CC BY-SA 3.0
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Dec 14, 2013 at 19:25 comment added Marc Palm Yes, the one-dimensional representation is the trivial one and is spherical.
Dec 14, 2013 at 19:19 comment added user7894 The non-spherical part has no reason to be finite dimensional, has it ?
Dec 14, 2013 at 18:24 history edited Marc Palm CC BY-SA 3.0
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Dec 14, 2013 at 17:38 history edited Marc Palm CC BY-SA 3.0
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Dec 14, 2013 at 17:37 comment added Asaf @PM, I'm given the impression that the OP asked about infinite-volume spectral theory.
Dec 14, 2013 at 17:31 history edited Marc Palm CC BY-SA 3.0
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Dec 14, 2013 at 17:19 history edited Marc Palm CC BY-SA 3.0
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Dec 14, 2013 at 17:12 history answered Marc Palm CC BY-SA 3.0