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Sep 17, 2013 at 2:51 answer added Neil Hoffman timeline score: 3
Sep 17, 2013 at 1:23 answer added Dan timeline score: 3
Feb 14, 2010 at 14:58 vote accept Steve D
Feb 14, 2010 at 14:57 answer added Steve D timeline score: 7
Feb 13, 2010 at 21:37 comment added Steve Huntsman mathforum.org/kb/message.jspa?messageID=6963952&tstart=0
Feb 13, 2010 at 18:17 comment added Steve D Yeah that follows since $x^3=y^5$ implies $x^3$ is in both $<x>$ and $<y>$ which means it's centralized by both $x$ and $y$.
Feb 13, 2010 at 18:05 comment added Steve Huntsman As Richard Kent pointed out in an answer I deleted, $yxy = x^2$, so $yx = x^2y^{-1}$ and $yxyx = x^3 \implies yxx^2y^{-1} = x^3$, so $x^3y = yx^3$. So all of the words in the relations of this presentation are in the center of $G$.
Feb 13, 2010 at 16:23 answer added Victor Miller timeline score: 13
Feb 13, 2010 at 15:42 answer added Joel David Hamkins timeline score: 14
Feb 13, 2010 at 10:42 history asked Steve D CC BY-SA 2.5