Skip to main content
14 events
when toggle format what by license comment
Jul 23, 2010 at 20:06 answer added Gilead timeline score: 0
Feb 15, 2010 at 1:05 vote accept Legend
Feb 13, 2010 at 14:39 answer added Harald Hanche-Olsen timeline score: 1
Feb 12, 2010 at 23:47 comment added Legend Also, I am sorry. I just realized I missed something from the question. Updated it with a second differential equation (but I'm not sure how relevant it is to the overall methodology that I was following).
Feb 12, 2010 at 23:46 history edited Legend CC BY-SA 2.5
added 25 characters in body; added 1 characters in body
Feb 12, 2010 at 23:43 comment added Legend @Steve: Yes... You are right (but I hate to accept this, because pretty much everything boils down ultimately to physics... Pardon me if I've mistaken). It is more from a problem I am seeing inside the domain of social networks, more specifically, the propagation of a message amongst a set of connected nodes.
Feb 12, 2010 at 23:39 comment added Steve Huntsman It doesn't look like the E-L equations have a solution for $A \ne 0$, and they're trivially satisfied if $A = 0$. This motivates the following Conjecture: your problem does not originate from physics.
Feb 12, 2010 at 23:33 history edited Steve Huntsman
added tag
Feb 12, 2010 at 23:33 comment added Legend @Steve: Currently looking into it.. Thanks. @Leonid: Yes.. All those are positive.
Feb 12, 2010 at 23:28 comment added Steve Huntsman Maybe I'm misunderstanding your question, but I think you just need to solve the Euler-Lagrange equations ( en.wikipedia.org/wiki/Euler%E2%80%93Lagrange_equation ) for the Lagrangian $\mathcal{L}(t,R,\dot R) = AR -\frac{1}{a}(\frac{\dot R}{R} + b)$. Also see calculus of variations: en.wikipedia.org/wiki/Calculus_of_variations
Feb 12, 2010 at 23:20 history edited Legend CC BY-SA 2.5
edited body; edited body
Feb 12, 2010 at 23:08 history edited Legend CC BY-SA 2.5
added 31 characters in body
Feb 12, 2010 at 23:07 comment added Legend Sorry... A is another parameter. I will clarify this in the question. And no, I meant (AR-x) inside the integral.
Feb 12, 2010 at 22:54 history asked Legend CC BY-SA 2.5