Timeline for If two projections are close, then they are unitarily equivalent
Current License: CC BY-SA 3.0
3 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 11, 2013 at 3:48 | comment | added | voldemort | Well- kernel of p= range of 1-p. ||(1-p)- (1-q)||=||p-q||<1. | |
| Dec 11, 2013 at 2:41 | comment | added | Nik Weaver | Not quite --- you also need the dimensions of their kernels to be equal. | |
| Dec 11, 2013 at 2:38 | history | answered | voldemort | CC BY-SA 3.0 |