Timeline for If two projections are close, then they are unitarily equivalent
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| May 14, 2018 at 2:30 | comment | added | David Handelman | Here is a ring proof. Let $R$ be a ring with $1$. If both $a,b$ are idempotents in $R$ st $1\pm (a-b)$ are invertible, then there is a simple argument to show that $a = xbx^{-1}$ for some invertible $x$ in $R$. In a C*-algebra ordinary equivalence implies *-equivalence, and you're done. | |
| Oct 7, 2014 at 1:17 | vote | accept | Martin Argerami | ||
| Dec 18, 2013 at 17:54 | answer | added | Julien | timeline score: 5 | |
| Dec 11, 2013 at 2:56 | answer | added | Martin Argerami | timeline score: 11 | |
| Dec 11, 2013 at 2:40 | answer | added | Nik Weaver | timeline score: 8 | |
| Dec 11, 2013 at 2:38 | answer | added | voldemort | timeline score: 2 | |
| Dec 11, 2013 at 2:23 | answer | added | Qiaochu Yuan | timeline score: 12 | |
| Dec 11, 2013 at 0:42 | history | asked | Martin Argerami | CC BY-SA 3.0 |