Timeline for Is X_0(p) a Mumford curve over $Q_{p^2}$
Current License: CC BY-SA 3.0
6 events
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Aug 5, 2016 at 14:36 | comment | added | Adel BETINA | The number of generators is equal to the genus of $X_0(p)$. | |
Dec 7, 2013 at 2:42 | comment | added | David E Speyer | In principal, yes, Mumford's proof is constructive. And once you find any generators, arxiv.org/abs/1309.5243 will put them into a convenient normalized form. But I don't know how to get those generators in the first place. | |
Dec 7, 2013 at 1:48 | comment | added | Hugo Chapdelaine | Is it possible to give a finite list of explicit topological generators for $\Gamma$? | |
Dec 7, 2013 at 1:46 | vote | accept | Hugo Chapdelaine | ||
Dec 6, 2013 at 16:58 | history | edited | David E Speyer | CC BY-SA 3.0 |
added 33 characters in body
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Dec 6, 2013 at 16:40 | history | answered | David E Speyer | CC BY-SA 3.0 |