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Sep 19, 2014 at 3:15 vote accept Qiaochu Yuan
Dec 6, 2013 at 16:54 comment added user36931 Between Kahler manifolds and symplectic quotients (there is obviously some overlap here), you get a lot of the symplectic manifolds people care about.
Dec 6, 2013 at 16:51 comment added user36931 I was just pointing out that I see no reason e.g. the quintic three-fold in CP^4 (which is one of the most studied symplectic manifolds with it's standard Kahler form) is a quotient as above. Of course proving that seems difficult enough, but that seems irrelevant to what you are asking. Certainly it's not naturally presented that way and although the theory of symplectic quotients plays a role in that literature, it's not in this direct fashion.
Dec 6, 2013 at 2:50 comment added Qiaochu Yuan @user: yes, and?
Dec 6, 2013 at 2:22 comment added user36931 If you require finite dimensions, this is a rather hyperbolic claim--- consider an arbitrary projective variety.
Dec 6, 2013 at 2:12 answer added Francois Ziegler timeline score: 6
Dec 5, 2013 at 22:50 answer added Patrick I-Z timeline score: 11
Dec 5, 2013 at 22:02 history asked Qiaochu Yuan CC BY-SA 3.0