Timeline for Proving that Brownian motion has no points of increase
Current License: CC BY-SA 4.0
12 events
| when toggle format | what | by | license | comment | |
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| Apr 18, 2023 at 16:00 | history | edited | Glorfindel | CC BY-SA 4.0 |
broken link fixed, cf. https://meta.mathoverflow.net/q/5301/70594
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| Dec 14, 2014 at 2:19 | vote | accept | Irfan Alam | ||
| Dec 28, 2013 at 8:05 | answer | added | Bjørn Kjos-Hanssen | timeline score: 2 | |
| Dec 5, 2013 at 11:05 | history | edited | Irfan Alam | CC BY-SA 3.0 |
added 5 characters in body
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| Dec 5, 2013 at 10:33 | comment | added | Irfan Alam | That is the set of all $\omega$ such that there exist real numbers s and t(depending on $\omega$) for which the Brownian motion satisfies the conditions specified in the definition of the set. I have also linked the original paper of Burdzy(in my question) in which you can read these things for further clarifications. | |
| Dec 5, 2013 at 10:30 | history | edited | Irfan Alam | CC BY-SA 3.0 |
Clarified a few things.
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| Dec 5, 2013 at 10:19 | comment | added | Did | @AndrásBátkai The set is an event, that is, a subset of the probability space $\Omega$. | |
| S Dec 5, 2013 at 9:59 | history | suggested | Davide Giraudo | CC BY-SA 3.0 |
improved formatting, added a tag.
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| Dec 5, 2013 at 9:59 | review | Suggested edits | |||
| S Dec 5, 2013 at 9:59 | |||||
| Dec 5, 2013 at 8:34 | comment | added | András Bátkai | Are you sure the set is defined like that? What points are in it, $t$? Could you edit the question accordingly? | |
| Dec 5, 2013 at 8:23 | review | First posts | |||
| Dec 5, 2013 at 8:34 | |||||
| Dec 5, 2013 at 8:08 | history | asked | Irfan Alam | CC BY-SA 3.0 |