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Dec 6, 2013 at 17:32 vote accept Dave Futer
Dec 6, 2013 at 15:50 answer added Ricardo Andrade timeline score: 9
Dec 5, 2013 at 17:21 comment added Dave Futer If the codimension is 1, there are really easy counterexamples (take a curve in $R^2$ which is $C^2$ but not smooth). If the codimension is 2, I'm not sure. In any case, codimension 3 is what naturally came up in a problem that a colleague of mine is studying.
Dec 5, 2013 at 16:17 comment added Willie Wong Out of curiosity: Is there any particular reason why codimension at least 3? Are there known results for the case of lower codimension?
Dec 5, 2013 at 13:06 history edited Dave Futer CC BY-SA 3.0
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Dec 5, 2013 at 13:05 comment added Dave Futer Yes, smooth is $C^\infty$, and I'm asking about regularity issues.
Dec 5, 2013 at 8:58 review Close votes
Dec 5, 2013 at 10:18
Dec 5, 2013 at 8:45 comment added Willie Wong For immersed submanifolds: obviously not. For embedded submanifolds: use the constant rank theorem. Though maybe I am misunderstanding your question: is smooth $C^\infty$ here and are you asking about regularity issues? (If so, please edit to clarify, and in which case I retract my vote to close.)
Dec 4, 2013 at 21:40 history asked Dave Futer CC BY-SA 3.0