Timeline for Is there an integer a such that f(X)+a is irreducible in Z[X]?
Current License: CC BY-SA 3.0
4 events
when toggle format | what | by | license | comment | |
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Dec 2, 2013 at 17:04 | comment | added | Peter Mueller | O.K., Qiaochu Yuan's elegant and elementary answer does what you want. | |
Dec 2, 2013 at 15:34 | comment | added | l.t | Thank you. Indeed, I forgot about Gauss Lemma, so I feel silly asking about $\mathbb{Q}[X]$ now. However, Hilbert's Theorem is too advanced for me, unless there is a simple proof for this case. I was thinking to look for big primes, but I haven't found anything useful yet. | |
S Dec 2, 2013 at 15:28 | history | answered | Peter Mueller | CC BY-SA 3.0 | |
S Dec 2, 2013 at 15:28 | history | made wiki | Post Made Community Wiki by Peter Mueller |