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May 10, 2010 at 18:50 vote accept Hej
Feb 12, 2010 at 1:41 comment added George Lowther Bjorn - it still gets a little messy choosing the binary digits correctly. Your answer seems pretty good to me and, as it's way past my bedtime now, I'll leave it at that.
Feb 12, 2010 at 1:39 comment added George Lowther I don't know if picking a z at random like that will work but, according to my response, the chances of it working are zero:)
Feb 12, 2010 at 1:17 comment added Victor Miller Bjorn, very nice! I wonder if it's possible to describe a $z$ that works more explicitly? We know that $\theta = \arg(z)/2\pi$ must be irrational, so it would be interesting to start with a particular case, say $\theta = \sqrt{2}-1$, and see if we can find a value for $|z|$ that works.
Feb 12, 2010 at 1:14 comment added Bjorn Poonen Yes. In fact, your approach has the advantage that it gives a more explicit theta. Sorry for posting my solution just as you were about to post yours.
Feb 12, 2010 at 0:48 comment added George Lowther Ok, cool. I was about to write something similar as per my comment above, using the binary expansion of theta/pi using the idea behind the construction of the Liouville constant. Think it boils down to the same basic idea as this answer though.
Feb 12, 2010 at 0:45 history edited Bjorn Poonen CC BY-SA 2.5
corrected the justification for the existence of I_j
Feb 12, 2010 at 0:39 history answered Bjorn Poonen CC BY-SA 2.5