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Post Reopened by Derek Holt, Ricardo Andrade, Jack Huizenga, Lucia, Peter Mueller
minor edit: added tag 'finite-groups' (question had just been bumped to the top)
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Ricardo Andrade
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clarified OP's question
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Guntram
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Let $G$ be a finite group and $H$ be a subgroup of $G$. ForSuppose that for any prime power order element $x$ of $G$, if there exsitsexists some element $g$ in $G$ such that $x^g$ is contained in $H$, can we get. Does it follow that $G=H$$H=G$?

Let $G$ be a finite group and $H$ be a subgroup of $G$. For any prime power order element $x$ of $G$, if there exsits some element $g$ in $G$ such that $x^g$ is contained in $H$, can we get $G=H$?

Let $G$ be a finite group and $H$ be a subgroup of $G$. Suppose that for any prime power order element $x$ of $G$, there exists some element $g$ in $G$ such that $x^g$ is contained in $H$. Does it follow that $H=G$?

[Edit removed during grace period]
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edited body; edited title
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