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Timeline for Fundamental Cycles of a graphs

Current License: CC BY-SA 3.0

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Mar 10, 2014 at 19:10 history edited David Eppstein CC BY-SA 3.0
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Dec 16, 2013 at 20:03 vote accept hbm
Dec 4, 2013 at 7:30 comment added David Eppstein Yes, a largest set, and they're all trees iff they all have exactly $n-1$ edges.
Dec 4, 2013 at 6:11 comment added Brendan McKay I think you mean "a" largest set; but if one is a tree than they all are. Right?
Dec 4, 2013 at 3:35 comment added David Eppstein The subsets of edges that do not include any cycles form the independent sets of a matroid. The subsets of edges that don't include all of the unique edges of some cycle form the independent sets of a different matroid. When you have two matroids on the same elements, you can find the largest set that's independent for both of them, in polynomial time. If this set is a tree, you've solved the problem, and if not there is no solution.
Dec 4, 2013 at 1:40 comment added hbm I am sure I follow. Could you explain?
Nov 29, 2013 at 0:16 history answered David Eppstein CC BY-SA 3.0