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Nov 23, 2013 at 16:10 history closed Benoît Kloeckner
Daniel Moskovich
Chris Godsil
Carlo Beenakker
David White
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Nov 23, 2013 at 9:04 review Close votes
Nov 23, 2013 at 16:10
Nov 23, 2013 at 8:45 comment added DavidLHarden (And I removed superfluous elements of my reasoning.)
Nov 23, 2013 at 8:39 history edited DavidLHarden CC BY-SA 3.0
re-inserted line break before parenthetical remark
Nov 23, 2013 at 8:37 comment added DavidLHarden Yes. Yes it is. I logged in because I just realized this.
Nov 23, 2013 at 3:26 answer added S. Carnahan timeline score: 2
Nov 23, 2013 at 1:42 comment added Qiaochu Yuan Why isn't this just the subgroup of all $k$ such that $kS = S$ (so the stabilizer of $S$ in $2^G$)?
Nov 23, 2013 at 1:30 history asked DavidLHarden CC BY-SA 3.0