Timeline for Is a unitary representation always semisimple?
Current License: CC BY-SA 3.0
5 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Nov 22, 2013 at 16:00 | comment | added | Windi | Thanks, user43112. But it seems to me that the proof of the lemma in Murnaghan's note does't use the smoothness of the representation, even though the lemma assumes the representation is smooth. So I edited the question itself accordingly. | |
| Nov 22, 2013 at 15:26 | comment | added | Marc Palm | A representation which is infinite-dimensional for SL_2(Q_p) and smooth, can't be unitary, only unitarizable. For example, the right translation on $C_c^\infty(G)$ is certainly smooth, its unitarisation is $L^2(G)$, but it can't be decomposable into a direct sum, but only a direct integral. | |
| S Nov 22, 2013 at 8:50 | review | Low quality posts | |||
| Nov 22, 2013 at 9:33 | |||||
| S Nov 22, 2013 at 8:50 | review | First posts | |||
| Nov 22, 2013 at 8:54 | |||||
| Nov 22, 2013 at 8:33 | history | answered | user43112 | CC BY-SA 3.0 |