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Mar 30, 2021 at 9:13 comment added username Harnack is for the convergence
Nov 22, 2013 at 4:23 comment added Kelei Wang I don't know where to use Harnack. Maybe the bound on $v_k$ (which I forgot)? But it seems unnecessary to use Harnack inequality. By the second assumption with uniform bound on $\Delta v_k$, I think we can get a uniform bound for $\|v_k\|_{L^1}$.
Nov 21, 2013 at 10:04 comment added gin111 ok, this is a standard argument but where do I use Harnack?
Nov 21, 2013 at 6:13 history answered Kelei Wang CC BY-SA 3.0