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Nov 28, 2013 at 4:08 comment added Bullmoose @Skoro Are there random variables whose tails decay exponentially that have infinite (or undefined) variance?
Nov 28, 2013 at 4:07 comment added Bullmoose @Waldemar Been working with your suggestion before going away for a few days... Haven't gotten the result I need yet. Didn't know about the truncated Cheybyshev's inequality before, it's neat. Thanks for the pointer to the book -- I do realize it's one of the first results when one searches for "truncated Chebyshev's inequality" but it's quite good.
Nov 23, 2013 at 17:45 comment added Skoro How about the following for a simple lower bound: $$P\left(\frac{1}{n}X_i - \mu_X > x\right)\geq \left[P(X_i - \mu_X > x)\right]^n.$$ This turns out to be sufficiently tight in certain cases, for instance, when $P(X_1 > x)$ goes down exponentially in $x$.
Nov 23, 2013 at 14:36 answer added ofer zeitouni timeline score: 2
Nov 20, 2013 at 15:46 answer added Bill Johnson timeline score: 2
Nov 20, 2013 at 8:18 comment added Waldemar If you cannot use Chebyshev’s inequality (because of the infinite variance) you can always consider applying “truncated Chebyshev inequality” – see e.g. books.google.pl/…
Nov 20, 2013 at 5:38 history asked Bullmoose CC BY-SA 3.0