Skip to main content
4 events
when toggle format what by license comment
Nov 20, 2013 at 16:32 comment added Elisabeth Fink Sorry, yes of course then it holds because we can replace a palindrome of the form gxg by gx^{o(x)-1}g, where now o(x)-1 is even if o(x) is coprime to $2$, hence odd.
Nov 20, 2013 at 16:30 comment added Elisabeth Fink This only works if the generators of $G$ don't have finite orders coprime to $2$. Could it still hold in some cases if we know that the generators of $G$ have finite orders coprime to $2$?
Nov 19, 2013 at 18:03 comment added Elisabeth Fink Thanks! This also answers if it could be true if G was a soluble group!
Nov 19, 2013 at 16:12 history answered Jeremy Rickard CC BY-SA 3.0