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Apr 13, 2017 at 12:58 history edited CommunityBot
replaced http://mathoverflow.net/ with https://mathoverflow.net/
Nov 18, 2013 at 16:23 vote accept Joseph O'Rourke
Nov 18, 2013 at 6:34 answer added Igor Pak timeline score: 14
Nov 18, 2013 at 2:46 comment added Will Jagy math.ucr.edu/home/baez/octonions/integers/integers_4.html
Nov 18, 2013 at 1:18 comment added Qiaochu Yuan A rough estimate of the number of constraints is that an $n$-simplex has $n!$ flags, and regularity means that the symmetry group acts transitively on flags.
Nov 18, 2013 at 1:16 comment added Joseph O'Rourke Excellent point, @QiaochuYuan! I wonder if that intuition can be made more precise, that constraints outrun freedom...?
Nov 18, 2013 at 1:14 comment added Qiaochu Yuan "Regular" seems like a more important adjective than "convex" in the title. Anyway, my intuition is that while the amount of room might increase, it doesn't increase as quickly as the number of constraints imposed by regularity. Graph embeddings, on the other hand, don't have to have any kind of symmetry properties.
Nov 18, 2013 at 1:12 history edited Joseph O'Rourke CC BY-SA 3.0
Clarifying (hopefully).
Nov 18, 2013 at 1:09 comment added Will Jagy Meanwhile, our own Jim Humphreys has a book math.umass.edu/~jeh/pub/book.html on Coxeter groups and reflection groups that probably gives a complete answer.
Nov 18, 2013 at 1:01 comment added Will Jagy I like Coxeter's book, Regular Polytopes. He wasn't just a pretty face.
Nov 18, 2013 at 0:55 history asked Joseph O'Rourke CC BY-SA 3.0