Timeline for Computing the Grothendieck-Springer resolution for $G = SL_2$
Current License: CC BY-SA 3.0
12 events
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Oct 25, 2020 at 19:12 | comment | added | Filip | Yes, I was wondering whether one knows exactly "which" extension is it. Interestingly, it is not written in the usual literature. | |
Oct 25, 2020 at 6:53 | comment | added | math no more | Depends on what you mean by known. There's no Birkhoff factorization, so getting a decomposition like this is probably not feasible. On the other hand, it's some extension of the cotangent bundle by a trivial bundle, corresponding to a map of vector spaces $\mathfrak{h} \rightarrow H^1(\Omega^1_{G/B})^G$, and I think one should be able to say what the map is. I don't know a reference and haven't fully worked out the details, but I think it should be an isomorphism. | |
Oct 23, 2020 at 0:55 | comment | added | Filip | Is this bundle known for arbitrary $\mathfrak{sl}_n$? | |
Feb 24, 2015 at 12:02 | history | edited | math no more | CC BY-SA 3.0 |
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Feb 24, 2015 at 11:49 | history | edited | math no more | CC BY-SA 3.0 |
cleaned up the proof a lot
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Jan 6, 2014 at 7:28 | history | edited | math no more | CC BY-SA 3.0 |
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Jan 6, 2014 at 7:06 | history | edited | math no more | CC BY-SA 3.0 |
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Nov 17, 2013 at 23:47 | history | edited | math no more | CC BY-SA 3.0 |
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S Nov 17, 2013 at 23:36 | review | Late answers | |||
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S Nov 17, 2013 at 23:36 | review | First posts | |||
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Nov 17, 2013 at 23:25 | history | edited | math no more | CC BY-SA 3.0 |
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Nov 17, 2013 at 23:20 | history | answered | math no more | CC BY-SA 3.0 |