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Nov 16, 2013 at 16:11 comment added Turbo Can we have $gcd(a,b)=gcd(c,d)=1$?
Nov 16, 2013 at 16:11 comment added joro @JAS I edited the answer. There might be smaller solution. Basically $x,y$ do not depend on $t$ at all, for fixed t they can be arbitrary large.
Nov 16, 2013 at 16:10 vote accept Turbo
Nov 16, 2013 at 16:53
Nov 16, 2013 at 16:09 history edited joro CC BY-SA 3.0
Added explanation
Nov 16, 2013 at 16:05 vote accept Turbo
Nov 16, 2013 at 16:10
Nov 16, 2013 at 16:04 comment added Turbo does the minimum number of bits in $x$ and $y$ always grow double exponential($2^{2^t}$) or faster in $t$? Could there be a smaller solution?
Nov 16, 2013 at 16:00 comment added Turbo does the same trick work for $t=3$? (Asking since mathematica came back empty handed).
Nov 16, 2013 at 15:58 history answered joro CC BY-SA 3.0