Skip to main content
5 events
when toggle format what by license comment
Nov 16, 2013 at 14:38 comment added Tom LaGatta The tricky part is regularity, then. This is the whole point of Kolmogorov's continuity theorem: the product construction does not guarantee regularity. I have to think about @John Dawkins' answer a little more.
Nov 16, 2013 at 9:58 comment added Adrien Hardy I'm kind of lost: as Michael Greinecker recalled, you can always build a huge probability space in which all your variables live, whatever $\Theta$ is, thanks to the tensor product construction. Then, maybe the "natural" topology you look for just the convergence in distribution of random variables ? In this case, that $x:\Theta\rightarrow L$ is continuous is by definition equivalent to $P:\Theta\rightarrow \Delta(X)$ continuous. But maybe I misunderstood the question.
Nov 16, 2013 at 8:51 comment added Michael Greinecker For the nontopological case, you can simply take $\Omega=X^\Theta$, $\mathcal{F}$ the product $\sigma$-algebry, $\mathbb{P}=\otimes_{\theta\in\Theta}P_\theta$ and $x_\theta$ the projection onto the $\theta$'s factor.
Nov 16, 2013 at 2:46 answer added John Dawkins timeline score: 4
Nov 15, 2013 at 23:06 history asked Tom LaGatta CC BY-SA 3.0