Timeline for Rational equivalence and infinitesimal deformation of curves
Current License: CC BY-SA 3.0
4 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Dec 3, 2013 at 12:40 | vote | accept | Jana | ||
| Nov 15, 2013 at 15:45 | answer | added | abx | timeline score: 2 | |
| Nov 15, 2013 at 15:34 | comment | added | Jason Starr | No, that is not true. Even if $C_1$ and $C_2$ have the same Hilbert polynomial, which is stronger than being rationally equivalent in $\mathbb{P}^3$, that is not true. Even if the two curves are parameterized by points in the same irreducible component of the Hilbert scheme, that is not true. Let $C_1$ be a twisted cubic, and let $C_2$ be a specialization of a twisted cubic whose reduced curve is a planar, nodal cubic, but with a spatial embedded point at the node. | |
| Nov 15, 2013 at 15:10 | history | asked | Jana | CC BY-SA 3.0 |