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Nov 12, 2013 at 2:55 comment added Douglas Zare How is fixing a particle at the center of the box equivalent to letting the sphere move with a particle? Even without boundary effects, subtracting one Brownian motion from multiple independent Brownian motions gives you dependent Brownian motions.
Nov 11, 2013 at 16:39 comment added Nate Eldredge Where do the particles start? What happens when they hit the boundary of the box?
Nov 11, 2013 at 11:25 history edited Stefan Kohl
Added 'pr.probability' toplevel tag.
Nov 11, 2013 at 10:35 review First posts
Nov 11, 2013 at 11:25
Nov 11, 2013 at 10:18 history asked user42638 CC BY-SA 3.0