Skip to main content
added 24 characters in body
Source Link
domotorp
  • 19k
  • 3
  • 58
  • 127

No, thisThe answer is falsenegative if you allow holes. Consider a 5 times 5 square with its center missing. Then the 4 squares adjacent to the center form an antirectangle, but any antirectangle that contains a corner square has at most three squares.

No, this is false. Consider a 5 times 5 square with its center missing. Then the 4 squares adjacent to the center form an antirectangle, but any antirectangle that contains a corner square has at most three squares.

The answer is negative if you allow holes. Consider a 5 times 5 square with its center missing. Then the 4 squares adjacent to the center form an antirectangle, but any antirectangle that contains a corner square has at most three squares.

Source Link
domotorp
  • 19k
  • 3
  • 58
  • 127

No, this is false. Consider a 5 times 5 square with its center missing. Then the 4 squares adjacent to the center form an antirectangle, but any antirectangle that contains a corner square has at most three squares.