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Nov 7 at 7:42 vote accept domotorp
Nov 7 at 7:05 answer added domotorp timeline score: 6
Jun 27, 2020 at 18:13 comment added domotorp @Tobias No, this question is quite different.
Jun 27, 2020 at 12:13 comment added Tobias Fritz This question seems to be the same as (or at least closely related to) multiplayer nontransitive dice. If I understand correctly, for example Oskar dice provide a solution with $t=2$, $n=21$ and $|\mathcal{F}| = 7$, the same parameters as in David Speyer's solution.
Jun 27, 2020 at 10:21 history edited domotorp CC BY-SA 4.0
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S Sep 19, 2017 at 13:13 history bounty ended CommunityBot
S Sep 19, 2017 at 13:13 history notice removed CommunityBot
Sep 12, 2017 at 4:48 history edited Martin Sleziak
removed (tag-removed) tag (The question has been bumped anyway.)
Sep 11, 2017 at 11:33 history edited domotorp CC BY-SA 3.0
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S Sep 11, 2017 at 11:32 history bounty started domotorp
S Sep 11, 2017 at 11:32 history notice added domotorp Draw attention
Apr 13, 2017 at 12:58 history edited CommunityBot
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Feb 18, 2014 at 21:39 answer added Sam Zbarsky timeline score: 22
Dec 2, 2013 at 9:47 vote accept domotorp
Oct 17, 2017 at 20:40
Nov 27, 2013 at 17:57 answer added David E Speyer timeline score: 29
Nov 25, 2013 at 22:28 history edited domotorp CC BY-SA 3.0
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S Nov 24, 2013 at 16:39 history bounty ended CommunityBot
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Nov 19, 2013 at 15:16 comment added Lev Borisov After trying for a while, my guess is that the strong version is unlikely to be achieved, but I have no proof to the contrary.
Nov 18, 2013 at 14:33 comment added domotorp Indeed, I have never realized that! To be honest, never got further than trying to prove the weak version for t=2...
Nov 18, 2013 at 0:35 comment added Lev Borisov Just pointing out the obvious: a strong version for $t=2$ and arbitrary $\epsilon$ implies strong version for any $t$.
Nov 16, 2013 at 20:59 comment added domotorp @Seva: No, I could not.
Nov 16, 2013 at 19:32 comment added Seva For $t=2$, one needs $n\ge 5$. Could you rule out the case $n=5$?
S Nov 16, 2013 at 15:00 history bounty started domotorp
S Nov 16, 2013 at 15:00 history notice added domotorp Draw attention
Nov 11, 2013 at 6:28 comment added domotorp I rewrote is as I've indicated it in my comment.
Nov 11, 2013 at 1:19 comment added Włodzimierz Holsztyński I'd suggest, @domotorp, that instead of answering Seva's and other doubts with a comment by you, you'd rewrite your question, please.
Nov 11, 2013 at 0:26 comment added Gerhard Paseman Maybe you can adapt a Hadamard design. Let the rows of a 7x7 0-1 matrix of maximal determinant be the seven functions. We don't have strict inequality, but any row is equal to or greater than the max of two other rows on 4 and sometimes 5 of the columns. Gerhard "Maybe It's A Design Problem" Paseman, 2013.11.10
Nov 10, 2013 at 17:40 comment added Suvrit this reminds me of an ultrametric ....
Nov 10, 2013 at 15:54 history edited domotorp CC BY-SA 3.0
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Nov 10, 2013 at 13:51 comment added domotorp Sorry, I just want to know if there is an n, I don't want all n's, I changed the first line.
Nov 10, 2013 at 13:50 history edited domotorp CC BY-SA 3.0
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Nov 10, 2013 at 13:49 comment added domotorp Taking all different values means that for any i, j, k, l we have $f_i(k)\ne f_j(l)$. Btw, this condition is in fact redundant, so you can ignore it if you wish.
Nov 10, 2013 at 10:52 comment added Seva Is $n$ assumed to be large in terms of $t$? (Otherwise, even the cases $n=1$ and $n=2$ seem to present a problem.)
Nov 10, 2013 at 10:41 comment added Seva Exactly what do you mean by "taking all different values"?
Nov 10, 2013 at 9:12 history asked domotorp CC BY-SA 3.0