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Timeline for Hausdorff measure and projections

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Nov 10, 2013 at 22:38 vote accept Axiom
Nov 10, 2013 at 22:38
Nov 10, 2013 at 21:24 comment added Pietro Majer In this case I think the answer should be no (see my answer below). Maybe assuming the stronger condition $H^k(\pi(A))=0$ for any projector $\pi$ with finite dimensional range allows a positive answer?
Nov 10, 2013 at 21:10 answer added Pietro Majer timeline score: 4
Nov 10, 2013 at 17:41 comment added Axiom The standard metric on $ \ell^\infty $ which is the supremum metric. And you're right. I should've been more careful about the projections. I meant to say projection onto the first m components. $ \pi_V(x_1, x_2, \dots) = (x_1, \dots, x_m) $.
Nov 10, 2013 at 8:42 comment added Anton Petrunin For $\ell^2$ the answer seems to be no, for orthogonal projections. For $\ell^\infty$ it is not clear which metric you want to consider on $A$ and which projections
Nov 9, 2013 at 21:20 history asked Axiom CC BY-SA 3.0