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Nov 13, 2013 at 17:09 vote accept IMeasy
Nov 13, 2013 at 16:40 answer added Sándor Kovács timeline score: 2
Nov 8, 2013 at 17:49 comment added IMeasy Of course, I found it. But it does not seem to answer my question.
Nov 8, 2013 at 17:02 history edited IMeasy CC BY-SA 3.0
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Nov 8, 2013 at 16:47 comment added Abdelmalek Abdesselam Did you find for instance: mathoverflow.net/questions/139153/…
Nov 8, 2013 at 14:58 comment added IMeasy I searched but could not find very much
Nov 8, 2013 at 13:45 comment added Jim Humphreys @IMeasy: You would probably get some insight from earlier questions raised on MO. Search for 'Reynolds operator'.
Nov 8, 2013 at 11:00 comment added Francesco Polizzi As far as I remember, you need both $(1)$ Hilbert's basis Theorem and $(2)$ Reynolds Identity in order to show that the invariant subspace $\mathcal{A}^G$ is a finitely generated $\mathbb{C}$-algebra.
Nov 8, 2013 at 10:32 history asked IMeasy CC BY-SA 3.0