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Nov 8, 2013 at 12:47 comment added Misha @HJRW: Yes, I should have, but I was doing this on a tiny screen...
Nov 8, 2013 at 10:38 comment added HJRW @J.C.Wu, you might be interested in Scott's paper 'Subgroups of surface groups are almost geometric'.
Nov 8, 2013 at 10:36 comment added HJRW @Misha, since you say it would be more suitable on MSE, I wonder why you didn't vote to migrate it there?
Nov 8, 2013 at 10:35 history closed Andy Putman
Will Jagy
Daniel Moskovich
Misha
HJRW
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Nov 8, 2013 at 9:31 history edited J.C. Wu CC BY-SA 3.0
added 24 characters in body
Nov 8, 2013 at 9:24 history edited J.C. Wu CC BY-SA 3.0
added 24 characters in body
Nov 8, 2013 at 9:23 comment added J.C. Wu I mean: can we find a non-surjective self map f:S→S such that f(S) is a submanifold.
Nov 8, 2013 at 8:31 comment added Misha @MarkGrant: I voted to close because it is more suitable for MSE. To begin with, it is based on a false premise that non-epimorphism can be induced by a non-surjective map (think of finite covers of the torus to itself); however, this false premise does hold in the higher genus case (why?). Secondly, any continuous map $f: M^m\to N^n$ is homotopic to a surjective map (think of a Peano curve).
Nov 8, 2013 at 7:19 comment added Francesco Polizzi Taking $\mathbb{T}^2= S^1 \times S^1$, the real $2$-torus, one has $\pi_1(\mathbb{T}^2)=\mathbb{Z} \oplus \mathbb{Z}$. Taking as $\phi$ the projection onto one of the factors, it seems to me that the image of the corresponding self-map $\mathbb{T}^2 \to \mathbb{T}^2$ is a copy of $S^1$.
Nov 8, 2013 at 7:03 comment added Mark Grant Could the people voting to close please explain why?
Nov 8, 2013 at 6:17 review Close votes
Nov 8, 2013 at 10:39
Nov 8, 2013 at 5:47 review First posts
Nov 8, 2013 at 7:24
Nov 8, 2013 at 5:30 history asked J.C. Wu CC BY-SA 3.0