Skip to main content
7 events
when toggle format what by license comment
Nov 16, 2015 at 22:20 comment added Gil What about Donoho's pseudo polar Fourier transforms? These algorithms work well.
Nov 9, 2013 at 3:49 history edited Michael Hardy CC BY-SA 3.0
added 3 characters in body
Nov 8, 2013 at 17:28 comment added Andrei MF @Carl The formulas that the ENZ theory gets using Zernike polynomials involve evaluation of infinite series of Bessel functions times certain binomial coefficients. Moreover, the terms of these sums are sign-changing and occasionally of similar size, thus cancellation errors might become a problem.
Nov 8, 2013 at 16:45 comment added user25199 Sorry - you're right, though it might still simplify if you express $f$ as a Fourier series in $\theta$. Why are the Zernike polynomials unsatisfactory?
Nov 8, 2013 at 15:33 comment added Andrei MF @Carl I think so, $\phi$ is sitting in the cosine (argument of the exponential).
Nov 8, 2013 at 9:04 comment added user25199 Does your integral actually depend on $\phi$?
Nov 7, 2013 at 23:43 history asked Andrei MF CC BY-SA 3.0