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Meant A_4 and S_3, not C_4 and C_3
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Stefan Kohl
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The 4-dimensional, i.e. $3 \times 3 \times 3 \times 3$, equivalent of the Rubik's cube has 8 three-dimensional sides, each of which consists of $3^3 = 27$ three-dimensional colored "squares". Of these 27 "squares", the one in the center is fixed. Thus in total our 4-dimensional Rubik's cube has $8 \cdot 26 = 208$ movable "squares", and the group of its sequences of moves under composition embeds therefore into ${\rm S}_{208}$.

Now just as the usual 3-dimensional Rubik's cube has 2 kinds of movable cubies (edge stones and corner stones), our 4-dimensional Rubik's cube has 3 distinct kinds of movable cubies:

  • The corner stones, of which there are $2^4 = 16$.

    Each corner stone has 4 visible colored "squares".

  • The edge stones, of which there are $2 \cdot 12 + 8 = 32$.

    Each edge stone has 3 visible colored "squares".

  • The face stones, of which there are $2 \cdot 6 + 12 = 24$.

    Each face stone has 2 visible colored "squares".

Therefore, analogous to the usual 3-dimensional case, we can finally say that our 4-dimensional Rubik's cube group embeds into the following direct product of wreath products: $$ {\rm C}_4 \wr {\rm S}_{16} \times {\rm C}_3 \wr {\rm S}_{32} \times {\rm C}_2 \wr {\rm S}_{24}. $$$$ {\rm A}_4 \wr {\rm S}_{16} \times {\rm S}_3 \wr {\rm S}_{32} \times {\rm C}_2 \wr {\rm S}_{24}. $$

The 4-dimensional, i.e. $3 \times 3 \times 3 \times 3$, equivalent of the Rubik's cube has 8 three-dimensional sides, each of which consists of $3^3 = 27$ three-dimensional colored "squares". Of these 27 "squares", the one in the center is fixed. Thus in total our 4-dimensional Rubik's cube has $8 \cdot 26 = 208$ movable "squares", and the group of its sequences of moves under composition embeds therefore into ${\rm S}_{208}$.

Now just as the usual 3-dimensional Rubik's cube has 2 kinds of movable cubies (edge stones and corner stones), our 4-dimensional Rubik's cube has 3 distinct kinds of movable cubies:

  • The corner stones, of which there are $2^4 = 16$.

    Each corner stone has 4 visible colored "squares".

  • The edge stones, of which there are $2 \cdot 12 + 8 = 32$.

    Each edge stone has 3 visible colored "squares".

  • The face stones, of which there are $2 \cdot 6 + 12 = 24$.

    Each face stone has 2 visible colored "squares".

Therefore, analogous to the usual 3-dimensional case, we can finally say that our 4-dimensional Rubik's cube group embeds into the following direct product of wreath products: $$ {\rm C}_4 \wr {\rm S}_{16} \times {\rm C}_3 \wr {\rm S}_{32} \times {\rm C}_2 \wr {\rm S}_{24}. $$

The 4-dimensional, i.e. $3 \times 3 \times 3 \times 3$, equivalent of the Rubik's cube has 8 three-dimensional sides, each of which consists of $3^3 = 27$ three-dimensional colored "squares". Of these 27 "squares", the one in the center is fixed. Thus in total our 4-dimensional Rubik's cube has $8 \cdot 26 = 208$ movable "squares", and the group of its sequences of moves under composition embeds therefore into ${\rm S}_{208}$.

Now just as the usual 3-dimensional Rubik's cube has 2 kinds of movable cubies (edge stones and corner stones), our 4-dimensional Rubik's cube has 3 distinct kinds of movable cubies:

  • The corner stones, of which there are $2^4 = 16$.

    Each corner stone has 4 visible colored "squares".

  • The edge stones, of which there are $2 \cdot 12 + 8 = 32$.

    Each edge stone has 3 visible colored "squares".

  • The face stones, of which there are $2 \cdot 6 + 12 = 24$.

    Each face stone has 2 visible colored "squares".

Therefore, analogous to the usual 3-dimensional case, we can finally say that our 4-dimensional Rubik's cube group embeds into the following direct product of wreath products: $$ {\rm A}_4 \wr {\rm S}_{16} \times {\rm S}_3 \wr {\rm S}_{32} \times {\rm C}_2 \wr {\rm S}_{24}. $$

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Stefan Kohl
  • 19.6k
  • 21
  • 75
  • 137

The 4-dimensional, i.e. $3 \times 3 \times 3 \times 3$, equivalent of the Rubik's cube has 8 three-dimensional sides, each of which consists of $3^3 = 27$ three-dimensional colored "squares". Of these 27 "squares", the one in the center is fixed. Thus in total our 4-dimensional Rubik's cube has $8 \cdot 26 = 208$ movable "squares", and the group of its sequences of moves under composition embeds therefore into ${\rm S}_{208}$.

Now just as the usual 3-dimensional Rubik's cube has 2 kinds of movable cubies (edge stones and corner stones), our 4-dimensional Rubik's cube has 3 distinct kinds of movable cubies:

  • The corner stones, of which there are $2^4 = 16$.

    Each corner stone has 4 visible colored "squares".

  • The edge stones, of which there are $2 \cdot 12 + 8 = 32$.

    Each edge stone has 3 visible colored "squares".

  • The face stones, of which there are $2 \cdot 6 + 12 = 24$.

    Each face stone has 2 visible colored "squares".

Therefore, analogous to the usual 3-dimensional case, we can finally say that our 4-dimensional Rubik's cube group embeds into the following direct product of wreath products: $$ {\rm C}_4 \wr {\rm S}_{16} \times {\rm C}_3 \wr {\rm S}_{32} \times {\rm C}_2 \wr {\rm S}_{24}. $$