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Feb 17, 2014 at 6:35 review Reopen votes
Feb 17, 2014 at 11:01
Jan 28, 2014 at 18:28 history closed Stefan Kohl
Andrey Rekalo
Ryan Budney
David Roberts
Neil Strickland
Duplicate of New differintegral formula: how is it related to other differintegral formulas?
Jan 10, 2014 at 4:53 comment added Theo Johnson-Freyd @Anixx Not off the top of my head. It's not really my area.
Jan 9, 2014 at 22:01 comment added Anixx @Theo Johnson-Freyd Can you give an example where it converges, but not to an antiderivative?
Jan 9, 2014 at 20:48 comment added Theo Johnson-Freyd Well, the answer is clearly "yes" for $f(x) = \exp(\lambda x)$ for $\lambda \in \mathbb C$ with $|\lambda-1|<1$, and therefore for linear combinations of such functions (more generally, e.g., if your Fourier transform has compact support in the interior of the disk). But I'm sure there are cases where F converges in some not-great way to some not-very-regular function.
Jan 9, 2014 at 20:23 comment added Anixx @Theo Johnson-Freyd no, I mean exactly that property.
Jan 9, 2014 at 18:23 comment added Theo Johnson-Freyd Why do you write $\binom{-1}m$ rather than $\frac{(-1)\cdots(-m)}{m!} = (-1)^m$? By "properties of an antiderivative", do you mean more than that $\partial F = f$?
Jan 9, 2014 at 17:37 review Close votes
Jan 28, 2014 at 18:28
Nov 7, 2013 at 11:42 comment added Anixx @Carlo Beenakker I think it does not answer the question because it does not mention the other types of differintegral, which I was asking for comparison with. From what I understand, it says that the continuity is difficult to prove. This question is more narrow, it asks about just antiderivative.
Nov 7, 2013 at 11:32 comment added Carlo Beenakker was the earlier answer unsatisfactory? mathoverflow.net/questions/130886
Nov 7, 2013 at 5:29 history asked Anixx CC BY-SA 3.0