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Nov 4, 2013 at 20:43 history closed Suvrit
Sergei Ivanov
Andrey Rekalo
Chris Godsil
Ian Agol
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Nov 4, 2013 at 18:03 review Close votes
Nov 4, 2013 at 20:44
Nov 4, 2013 at 17:43 comment added Suvrit $A \ge B \implies \lambda_i(A) \ge \lambda_i(B)$.
Nov 4, 2013 at 16:34 comment added Federico Poloni Horn and Johnson, Matrix Analysis, Corollary 7.7.4.
Nov 4, 2013 at 14:55 history edited Weeson Dorne CC BY-SA 3.0
added 20 characters in body
Nov 4, 2013 at 14:49 history asked Weeson Dorne CC BY-SA 3.0