Timeline for limit of a singular integral
Current License: CC BY-SA 3.0
8 events
| when toggle format | what | by | license | comment | |
|---|---|---|---|---|---|
| Jan 19, 2014 at 3:54 | answer | added | Felix Marin | timeline score: 2 | |
| Nov 5, 2013 at 9:16 | vote | accept | user16215 | ||
| Nov 4, 2013 at 1:50 | answer | added | Heis Wernerberg | timeline score: 1 | |
| Nov 3, 2013 at 10:27 | vote | accept | user16215 | ||
| Nov 5, 2013 at 9:16 | |||||
| Nov 2, 2013 at 12:05 | answer | added | fedja | timeline score: 10 | |
| Nov 2, 2013 at 9:32 | comment | added | user16215 | Yes please fedja I would be glad to read the full answer and vote for it ! | |
| Nov 2, 2013 at 9:25 | comment | added | fedja | Actually it is because you take $\delta>0$, show that almost half of the total mass of $f_\gamma(x)f_\gamma(y)\,dxdy$ is in $[1-\delta,1]^2\cup [-1,\delta-1]^2$ where you have $\log|x-y|<\log\delta$ and conclude (the positive part is, clearly, bounded). Since you can take $\delta\approx \gamma^{-1}$ here and $\log$ is a superlazy guy when it comes to moving anywhere, the crude asymptotics $-(\frac 12+o(1))\log\gamma$ is obvious too. Let me know if you want more precision because that will take some work... | |
| Nov 2, 2013 at 9:12 | history | asked | user16215 | CC BY-SA 3.0 |