Timeline for A property of bi-invarient Finsler metrics on SU(N)
Current License: CC BY-SA 3.0
4 events
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May 23, 2014 at 14:23 | comment | added | Benjamin | @ Prof Matveev, so can one then conclude that every Finsler metric on $SU(N)$ with the one parameter sub groups as it's geodesics (upto parametrisation?) is Riemannian? | |
Nov 2, 2013 at 20:56 | vote | accept | Benjamin | ||
Nov 2, 2013 at 20:56 | |||||
Nov 2, 2013 at 18:34 | comment | added | alvarezpaiva | The most pleasant definition of a Berwald metric is a Finsler metric whose parameterized geodesics are the geodesics of some affine connection. If you take this as a definition, then the fact you cite as well-known is a tautology. | |
Nov 1, 2013 at 16:49 | history | answered | Vladimir S Matveev | CC BY-SA 3.0 |